head 1.5; access; symbols; locks; strict; comment @# @; 1.5 date 2017.10.27.13.20.11; author root; state Exp; branches; next 1.4; 1.4 date 2017.06.18.01.16.47; author root; state Exp; branches; next 1.3; 1.3 date 2017.06.17.12.47.16; author root; state Exp; branches; next 1.2; 1.2 date 2017.06.16.15.06.48; author root; state Exp; branches; next 1.1; 1.1 date 2017.06.16.15.06.48; author root; state Exp; branches; next ; desc @This document (3.2 Average speed) is re-created by administrator on 29 March 2017 @ 1.5 log @This document (3.2 Average speed) is lastly updated by administrator status:PUBLISHED on 27 October 2017 @ text @{ "_id": { "$oid": "5943f4084975ac013d36fb03" }, "_type": "GSystem", "access_policy": "PUBLIC", "altnames": "3.2 Average speed", "annotations": [], "attribute_set": [], "author_set": [ 1 ], "collection_set": [], "comment_enabled": false, "content": "

\r\n\r\nAverage Speed

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\u2018d\u2019 denotes distance; \u2018t\u2019 denotes time. \u2206 is a Greek symbol used to denote the difference

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\r\nYou have the following data from scooter ride about the distance and time taken to complete the journey:

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\r\n\r\n\r\n\t\r\n\t\t\r\n\t\t\r\n\t\t\r\n\t\t\r\n\t\r\n\t\r\n\t\t\r\n\t\t\t\r\n\t\t\t\r\n\t\t\r\n\t\t\r\n\t\t\t\r\n\t\t\t\r\n\t\t\t\r\n\t\t\t\r\n\t\t\r\n\t\t\r\n\t\t\t\r\n\t\t\t\r\n\t\t\t\r\n\t\t\t\r\n\t\t\r\n\t\r\n

Ride starts	Ride ends
\r\n\t\t\t Time t₀(minute) \r\n\t\t\t	\r\n\t\t\tDistance, d₀ (km)	\r\n\t\t\t Time t₁ (minute)	\r\n\t\t\tDistance d₁(km)
0	\r\n\t\t\t 0 \r\n\t\t\t	\r\n\t\t\t 15 \r\n\t\t\t	\r\n\t\t\t 6 \r\n\t\t\t

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Table 3.2: Scooter Ride

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What was the total distance covered during the ride?
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Total distance covered, \u2206d = d₁ - d₀

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= 6 - 0 km
\r\n = 6 km

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\r\n
What was the time taken to cover this distance?
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Time taken to cover this distance, \u2206t = t₁ - t₀

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\r\n = 15-0 minutes

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\r\n = 15 minutes
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\r\n

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To calculate the average speed, we divide the total distance covered by the total time taken for the journey.

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\r\nSpeed, v = Total distance covered / time taken to cover this distance

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\r\n                 \$v = {\\Delta d \\over \\Delta t}\$
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\r\n       \$ = {6~km \\over 15~minutes}\$
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\r\n                 \$ = \$ 0.4 km / minute
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\r\nWhat does this number tell us?
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\r\nThe instantaneous speed of the scooter was changing throughout the 6 km journey. You know now that that the cooter took 15 minutes to cover this journey.
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\r\nWhat you get now, after calculating these two numbers is that, if the rider would go on with the constant speed of 0.4 km/minute, he would hvae covered the same distance ( 6 km) in the same time (15 minute). this speed is called the Average speed.
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\r\nThe average speed of an object gives us a rough idea about how fast or slow an object is traveling. It helps us to estimate or predict the future trends of the motion, which we often do on the daily basis.
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The Average Speed helps us to estimate future trends of the motion.

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Let us take another example to understand what an average speed is. The distance to a nearby town is 60km. A bus takes two hours to cover the distance. We can use the motion equation to find out that the average speed of the bus is 30km/hour. Knowing the average speed of the bus, we can now safely assume that it will take us two hours to reach the town. Of course, sometimes it may take a little more time if the bus halts many times along the route. Or it may take less time if the driver drives faster than 30km/hour.

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\r\nWe can calculate the average of any quantity which is similar, such as the average weight, height or age of students in a class.
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\r\n", "content_org": "We have the following data about the distance and time of the journey of the man on the scooter:\r\n

\r\n\t\t\t Ride starts \r\n\t\t\t	\r\n\t\t\t Ride ends \r\n\t\t\t
\r\n\t\t\t Distance (d 0 ) \r\n\t\t\t	\r\n\t\t\t Time (t0) \r\n\t\t\t	\r\n\t\t\t Distance (d1 ) \r\n\t\t\t	\r\n\t\t\t Time (t1 ) \r\n\t\t\t
\r\n\t\t\t \r\n\t\t\t	\r\n\t\t\t \r\n\t\t\t	\r\n\t\t\t \r\n\t\t\t	\r\n\t\t\t \r\n\t\t\t

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\r\n\r\nAverage Speed